Answer :
The pressure in the tank that contains oxygen (O₂) in different required units is 5,320 torr, 102.87 lb/in², 391.18 mmHg_g, and 709.275 kPa
Conversion of pressure to different unit
To solve this problem, first convert the pressure of oxygen in the tank from atm to all the other required units
Thus;
1 atm = 760 torr
1 atm = 14.696 lb/in²
1 atm = 760 mmHg
1 atm = 101.325 kPa
Pressure in torr
pressure in torr = 7.00 atm × 760 torr/atm
= 5,320 torr
Pressure in pounds per square inch (lb/in²)
pressure in lb/in² = 7.00 atm × 14.696 lb/in²/atm
= 102.87 lb/in²
Pressure in millimeters of mercury (mmHg)
pressure in mmHg = 7.00 atm × 760 mmHg/atm
= 5,320 mmHg
To convert this to mmHg_g, we need to multiply by the ratio of the density of mercury to the density of oxygen at the same temperature and pressure. At room temperature, the density of mercury is approximately 13.6 times greater than the density of oxygen.
Thus;
pressure in mmHg_g = 5,320 mmHg × (1/13.6)
= 391.18 mmHg_g
Pressure in kilopascals (kPa)
pressure in kPa = 7.00 atm × 101.325 kPa/atm
= 709.275 kPa
Therefore, the pressure in the tank in terms of kilopascals is 709.275 kPa, rounded to three significant figures.
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