Answer :
Using a t-distribution with 115 degrees of freedom (df = n-1), and a 95% confidence level, we can find the critical value using a t-table or calculator, which is approximately 1.98.
Then, we can calculate the margin of error (ME) using the formula:
ME = critical value x standard error
where the standard error (SE) is given by:
SE = standard deviation / sqrt(sample size)
Substituting the given values, we get:
SE = 30 / sqrt(116) ≈ 2.78
ME = 1.98 x 2.78 ≈ 5.5
Finally, we can construct the 95% confidence interval (CI) for the mean weight using the formula:
CI = sample mean ± margin of error
Substituting the given values, we get:
CI = 177 ± 5.5
CI ≈ [171.5, 182.5]
Therefore, the 95% confidence interval for the mean weight of the residents in the town is approximately [171.5, 182.5] pounds.
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