A student reads a barometer in the laboratory and finds the prevailing atmospheric pressure to be 716 mm Hg. Express this pressure in the following units:

1. Atmospheres (atm)
2. Kilopascals (kPa)
3. Torrs
4. Pounds per square inch (psi)
5. Pascals (Pa)

Hint:
1 atm = 101.3 kPa = 760 torr = 760 mm Hg = 14.69 psi = 1.013×10^5 Pa

To convert 716 mm Hg to other units of pressure, divide by the appropriate conversion factor. This gives you 0.942 atmospheres, 95.5 kPa, 544,960 torr, 0.942 psi, and 7.24×10^4 Pa.

Explanation:

To express atmospheric pressure from millimeters of mercury (mm Hg) to atmospheres, divide the pressure by the conversion factor of 760 mm Hg per atmosphere. Therefore, 716 mm Hg ÷ 760 mm Hg/atmosphere = 0.942 atmospheres.

To convert to kilopascals (kPa), multiply the pressure in atmospheres by the conversion factor of 101.3 kPa per atmosphere. Thus, 0.942 atmospheres × 101.3 kPa/atmosphere = 95.5 kPa. To convert to torr, simply use the conversion factor of 760 torr per atmosphere.

So, 716 mm Hg × 760 torr/mm Hg = 544,960 torr. To convert to pounds per square inch (psi), divide the pressure in mm Hg by the conversion factor of 760 mm Hg per psi. Hence, 716 mm Hg ÷ 760 mm Hg/psi = 0.942 psi.

Finally, to express the pressure in pascals (Pa), multiply by the conversion factor of 1.013×10^5 Pa per atmosphere. Therefore, 716 mm Hg × 1.013×10^5 Pa/atmosphere = 7.24×10^4 Pa.

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