Answer :
Final answer:
The leakage reactance and resistance in the secondary winding of a given transformer is calculated using the transformer's turns ratio. By applying the formulae based on primary side values and the turns ratio derived from the primary to secondary voltages, the correct values are found to be 7.56 for reactance, and 1.66 for resistance, corresponding to option A.
Explanation:
The student's question pertains to the calculation of leakage reactance and resistance in the secondary winding of a transformer.
Given are the values of reactance and resistance in the primary winding (high voltage side), and overall percentages of reactance and resistance for the transformer.
To find the reactance (Xs) and resistance (Rs) on the secondary side (low voltage), we utilize the transformer's turns ratio and the given percentages.
Since the transformer's rated reactance and resistance are 4% and 1% respectively, we can use the following formulae:
Xs = Xp * (Ns/Np)^2
Rs = Rp * (Ns/Np)^2
where Xp and Rp are the reactance and resistance on the primary side, and Ns/Np is the turns ratio of the secondary to primary. Here, the turns ratio is derived from the voltages, Ns/Np = Vprimary/Vsecondary = 13200/2400. Plugging in the values:
Xs = 6.34 * (13200/2400)^2
= 7.56
Rs = 1.83 * (13200/2400)^2
= 1.66
Thus, the correct answer is A. 7.56 , 1.66.
