High School

A student combined 37.2 mL of 1.69 M \( \text{KMnO}_4 \) solution with 16.10 mL of a 0.891 M \( \text{KMnO}_4 \) solution. Calculate the concentration of the final solution.

Answer :

1.45 M is concentration of the final solution.

volume, KMnO4 solution =37.2 mL

Molarity, KMnO4 solution =1.69 M

volume, KMnO4 solution =16.10 mL

Molarity, KMnO4 solution =0.891 M

The millimoles, KMnO4 solution = M x V (in mL)=1.69 x 37.2 =62.868 mmol

The millimoles, KMnO4 solution = M x V (in mL)=0.891 x 16.10 =14.3451 mmol

Total millimoles=62.868 +14.3451 =77.2131 mmol

Total volume = 37.2 + 16.10 =53.3 mL

Final concentration=77.2131 mmol/53.3 mL=1.4486 mol/L

Final concentration=1.45 M

In chemistry, concentration is the amount of a substance in a given space. Another definition of concentration is the proportion of the solute to the solvent or whole solution. Typically, mass per unit volume is used to denote concentration. However, the solute concentration can also be expressed in volumetric or molecular units. Instead of using volume, concentration can be stated as a mass per unit. Despite being frequently used to chemical solutions, concentration may be calculated for any combination.

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Final answer:

To determine the concentration of the final KMnO4 solution, the total moles of KMnO4 from both solutions were added and then divided by the total volume of the mixture, resulting in a concentration of 1.447 M.

Explanation:

The question involves calculating the concentration of a final solution after two solutions with known volumes and concentrations are combined. To find the concentration of the final solution, we first calculate the total number of moles of solute present in both solutions and then divide this number by the total volume of the solution in liters. For the first solution (37.2 mL of 1.69 M KMnO4), the number of moles of KMnO4 is calculated as (37.2 mL / 1000 mL/L) * 1.69 M = 0.062808 moles. For the second solution (16.10 mL of 0.891 M KMnO4), the number of moles is (16.10 mL / 1000 mL/L) * 0.891 M = 0.0143511 moles. The total moles of KMnO4 in the final solution is 0.062808 moles + 0.0143511 moles = 0.0771591 moles. The total volume of the final solution in liters is (37.2 mL + 16.10 mL) / 1000 = 0.0533 L. The concentration of the final solution is then the total moles divided by the total volume: 0.0771591 moles / 0.0533 L = 1.447 M (rounded to three significant figures).