Answer :
The velocity of the other piece is zero. It remains stationary after the fission.
We can apply the principle of conservation of momentum. Before the fission, the uranium nucleus is stationary, so its initial momentum is zero.
After the fission, the two pieces move in opposite directions. Let's denote the velocity of the piece with mass m as v₁ and the velocity of the piece with mass 1.5m as v₂.
According to the conservation of momentum:
(initial momentum) = (final momentum)
0 = m * v₁ + 1.5m * v₂
Since the 1.5m piece moves to the right (positive direction) with velocity v, we can express v_2 as v and v_1 as -v, as it moves in the opposite direction.
0 = m * (-v) + 1.5m * v
0 = -m * v + 1.5m * v
0 = 0.5m * v
From this equation, we can see that v must be zero for the momentum to be conserved. Therefore, the other piece's velocity is zero. After the fission, it remains stationary.
To know more about the Uranium nucleus, here
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