Answer :
The final speed of the object of mass 4.4 Kg when hit with an average force of 83.7 N is approximately 2.82 m/s (rounded to two digits of precision).
To calculate the final speed of the object, we can use the impulse-momentum theorem, which states that the change in momentum of an object is equal to the impulse applied to it.
Given:
Mass of the object (m) = 4.4 kg
Average force applied (F) = 83.7 N
Interaction time (Δt) = 147 milliseconds = 147 ms = 0.147 s (converted to seconds)
Impulse (J) = F × Δt
Now, the change in momentum (Δp) is given by the impulse:
Δp = J = F × Δt
The final speed (v_f) of the object can be calculated using the equation for momentum (p = m × v):
Δp = m × v_f - 0 (assuming the object starts from rest)
Now, rearrange the equation to solve for the final speed:
v_f = Δp / m
Substitute the values:
v_f = (F × Δt) / m
v_f = (83.7 N × 0.147 s) / 4.4 kg
v_f ≈ 2.8182 m/s
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