A spinner is divided into many sections of equal size. Some sections are red, some are blue, and the remaining are green. The probability of the arrow landing on a section colored red is 12/20. The probability of the arrow landing on a section colored blue is 6 /20. What is the probability of the arrow landing on a green-colored section?

A. 2/20

B. 6/20

C. 8/20

D. 18/20

Since there only 3 colors you add 12/20(Red) + 6/12(Blue) and get 18/20(Combined Red and Blue)

Then you take out the Combined red and blue from the total percentage or 20/20(All 3 Combined/Full spinner)-18/20(Combined red+blue)=2/20

The answer is A.2/20

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SravyaDa SravyaDa · Answer 2 · 2024-10-18T07:58:14-04:00

To find the probability of landing on a green section of the spinner, subtract the sum of the probabilities of landing on red and blue from the total probability, which yields 2/20.

The probability that the spinner lands on one of the colored sections is always the sum of the probabilities of landing on each individual color, which must equal to 1 (or 20/20 to match the fractions given in the question). Given that the probability of landing on red is 12/20 and the probability of landing on blue is 6/20, we can find the probability of landing on green by subtracting the sum of the probabilities of landing on red and blue from the total probability.

To find the probability of landing on a green section, we perform the following calculation:

Probability of landing on green = Total probability - (Probability of red + Probability of blue)

Probability of landing on green = 20/20 - (12/20 + 6/20) = 20/20 - 18/20 = 2/20.

Therefore, the correct answer is A. 2/20.