High School

A solution is made using 100.5 g of ethanol (mm = 46.07 g/mol) and 120.0 g of water (mm = 18.02 g/mol). What is the molality of the ethanol in the solution?

Answer :

Final answer:

The molality of ethanol in the solution is 18.2 mol/kg.

Explanation:

To calculate the molality of ethanol in the solution, we need to first calculate the moles of ethanol and the mass of water.

Given 100.5 g of ethanol and its molar mass (46.07 g/mol), divide the mass by the molar mass: 100.5 g / 46.07 g/mol = 2.18 mol of ethanol.

Find the mass of water: In the solution, there is 120.0 g of water.

Convert mass of water to kilograms: 120.0 g is equivalent to 0.120 kg.

Now Divide the moles of ethanol (2.18 mol) by the mass of water in kilograms (0.120 kg): 2.18 mol / 0.120 kg = 18.2 mol/kg. This is the molality of ethanol in the solution.

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