College

**Question 1:**

Given: 13 pieces of [tex]1/2 \text{ inch}[/tex] 11 rebar, 40 feet 0 inches are required for your project. If only 20 feet 0 inches lengths are available, how many will you need (lap is 24 diameters)?

**Question 2:**

Given: Your slab is [tex]45 \text{ feet } 9 \text{ inches} \times 65 \text{ feet } 5 \text{ inches}[/tex]. Calculate how many 750 SF rolls of [tex]6 \times 6 \times 10/10[/tex] WWF you will need (allow 10% lap).

**Question 3:**

Given: 1200 SF of [tex]8 \text{ inches} \times 8 \text{ inches} \times 16 \text{ inches}[/tex] CMU to lay with a crew of three that has a productivity rate of [tex]0.095 \text{ HRS/SF}[/tex]. Calculate the number of hours to complete the job.

Answer :

1. the total length of rebar required for the project is153 ft

2. The number of rolls required is 5 rolls of wire mesh

3. The number of hours to complete the job is 228 hours with each crew requiring 76 hours.

Calculating the number of hours required to complete the job

Calculation for rebar:

Each 40'-0" length of 1/2" diameter rebar contains 7.93 feet.

To determine the number of 20'-0" lengths required, divide the total length required by the available length:

Total length required = 13 pcs x 40'-0" x 1.0 ft/ft = 520 ft

Available length = 20'-0" x 1.0 ft/ft = 20 ft

Number of 20'-0" lengths required = (520 ft / 20 ft) + 1 = 27 lengths (rounded up to the nearest whole number)

To account for the lap length of 24 diameters, subtract the overlap length for each joint. Since the diameter of a 1/2" rebar is 0.5 inches, the overlap length is 12 inches (24 x 0.5 inches).

Therefore, the total overlap length for 13 joints is 156 inches (13 x 12 inches).

To convert the overlap length to feet, we divide by 12

Overlap length = 156 inches / 12 inches/ft = 13 ft

Therefore, the total length of rebar required for the project is

Total length = (13 pcs x 40'-0' + 13 ft) x 1.0 ft/ft = 553 ft

Calculation for wire mesh:

The total area of the slab is:

Area = 45'-9" x 65'-5" = (45 x 12 + 9) x (65 x 12 + 5) = 2,990 [tex]ft^2[/tex]

To account for a 10% lap, we need to increase the total area by 10%:

Total area with lap = [tex]2,990 ft^2 x 1.10 = 3,289 ft^2[/tex]

The area covered by each roll of wire mesh is

Roll area = 750[tex]ft^2[/tex]

Therefore, the number of rolls required is

Number of rolls = Total area with lap / Roll area = [tex]3,289 ft^2 / 750 ft^2[/tex]/roll = 4.38 rolls ~ 5 rolls of wire mesh to nearest whole number.

Calculation for CMU

The total surface area of the CMU is

Total surface area = [tex]1200 ft^2 * 2\ sides = 2400 ft^2[/tex]

The productivity rate of the crew is 0.095 hours per square foot, so the total time required is

Total time = Total surface area x Productivity rate = [tex]2400 ft^2 * 0.095 hrs/ft^2[/tex] = 228 hours

Since there are three crew members, we can divide the total time by three to get the time required for each worker

Time per worker = 228 hours / 3 workers = 76 hours

Therefore, the crew of three will require 76 hours to complete the job.

Learn more on Rebar on https://brainly.com/question/31944628

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