High School

A smoke particle has a mass of about 10−19 kg and a de Broglie wavelength of 10− 15 m, what is the velocity of this particle (in order of magnitude)? 103 m/s 104 m/s 100 m/s 102 m/s

Answer :

the correct option is 10^2 m/s.

m = 10^(-19) kg

λ = 10^(-15) m

h ≈ 6.626 × 10^(-34) J·s

v = (6.626 × 10^(-34) J·s) / ((10^(-19) kg) * (10^(-15) m))

= (6.626 × 10^(-34) J·s) / (10^(-34) J·m)

= 6.626 × 10^(-34 + 34) m/s

= 6.626 × 10^0 m/s

= 6.626 m/s

Rounded to the nearest order of magnitude, the velocity of the smoke particle is approximately 10^1 m/s. Therefore, the correct option is 10^2 m/s.

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