Answer :
561 cm because if you do the math mc = square you get that answr your welcome
Final answer:
To find the width of the illuminated area on the ground by the searchlight, we use trigonometry, specifically the tangent function, taking into account that the beam spreads out by a total of 5 degrees and the helicopter is at a height of 150 meters above the ground.
Explanation:
To calculate how wide an area the searchlight beam would illuminate on the ground, we need to consider the geometry involved. Since the searchlight is angled down at 70 degrees from the horizontal and the beam spreads out by 2.5 degrees to either side, we can use trigonometry to find the width of the light spot on the ground.
The total angle of the beam is 5 degrees (2.5 degrees on either side of the centre). The distance from the helicopter to the ground is 150 meters. We will apply the tangent function, which is the opposite side over the adjacent side in a right triangle. This gives us:
Width of illuminated area on the ground = 2 x (tan(2.5 degrees) x 150m)
First, convert the angle to radians since the tangent function works with radians: 2.5 degrees x π / 180.
Width of illuminated area on the ground = 2 x (tan(2.5 x π / 180) x 150m)
After calculating the tangent and multiplying by 150m, then doubling the result, you will get the total width of the illuminated area on the ground.
