High School

A screen is placed 36.6 cm from a single slit, which is illuminated with light of wavelength 618 nm. If the distance between the first and third minima in the diffraction pattern is 1.19 mm, what is the width of the slit?

Answer in units of mm.

Answer :

Final answer:

The width of the slit is approximately 0.189 mm.

Explanation:

To find the width of the slit, we can use the formula for the distance between minima in a single slit diffraction pattern:

d = (λL)/w

Where:

  1. d is the distance between minima
  2. λ is the wavelength of the light
  3. L is the distance from the screen to the slit
  4. w is the width of the slit

Plugging in the given values, we can rearrange the formula to solve for w:

w = (λL)/d

Substituting the values, we get:

w = (618 x 10-9 m) * (0.366 m) / (1.19 x 10-3 m)

w ≈ 189 μm or 0.189 mm

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