High School

A sample of gas (24.2 g) initially at 4.00 atm was compressed from 8.00 L to 2.00 L at constant temperature. What was the gas pressure after compression?

A. 1.00 atm
B. 2.56 atm
C. 2.00 atm
D. 16.0 atm

Answer :

The gas pressure after compressing the sample from 8.00 L to 2.00 L at constant temperature is 16.0 atm.

To find the gas pressure after compression, we can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume at a constant temperature.

Boyle's Law can be expressed as:

P1V1 = P2V2

where P1 and V1 are the initial pressure and volume, respectively, and P2 and V2 are the final pressure and volume, respectively.

Given:

Initial pressure (P1) = 4.00 atm

Initial volume (V1) = 8.00 L

Final volume (V2) = 2.00 L

Let's substitute these values into Boyle's Law:

P1V1 = P2V2

4.00 atm * 8.00 L = P2 * 2.00 L

32.00 atm * L = 2P2 * L

32.00 atm = 2P2

Dividing both sides by 2:

16.00 atm = P2

Therefore, the gas pressure after compression is 16.0 atm.

The gas pressure after compressing the sample from 8.00 L to 2.00 L at constant temperature is 16.0 atm.

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