Answer :
Final answer:
The original sample of copper-64 used in the procedure to study copper metabolism was 28 mCi. The size was calculated using the formula for radioactive decay.
Explanation:
The problem involves radioactive decay of copper-64 which can be solved by the formula for exponential decay, N = N0 * (1/2)^(t/T), where N is the final amount, N0 is the initial amount, t is the time that has passed, and T is the half-life of the substance. Given that N is 3.50 mCi, the half-life T is 13 hours, and the time t is 39 hours, you can rearrange the equation to solve for N0 (the initial amount): N0 = N / (1/2)^(t/T) = 3.50 mCi / (1/2)^(39/13) = 3.50 mCi / (1/2)^3 = 3.50 mCi / 0.125 = 28 mCi. So, the original sample of copper-64 used in the procedure studying copper metabolism was 28 mCi.
Learn more about Radioactive Decay here:
https://brainly.com/question/1770619
#SPJ11
