High School

A rotating wheel requires 3.03 seconds to rotate through 37.0 revolutions. Its angular speed at the end of the 3.03-second interval is 98.2 rad/s.

What is the constant angular acceleration of the wheel in rad/s²?

Answer :

The constant angular acceleration of the wheel is approximately 32.35 rad/s².

To find the constant angular acceleration of the wheel, we can use the following equation:

ωf = ωi + αt

where

ωf is the final angular speed,

ωi is the initial angular speed,

α is the angular acceleration,

and t is the time interval.

Given:

ωf = 98.2 rad/s

ωi = 0 rad/s (since the wheel starts from rest)

t = 3.03 s

Using the equation, we can solve for α:

α = (ωf - ωi) / t

Substituting the given values:

α = (98.2 rad/s - 0 rad/s) / 3.03 s

α ≈ 32.35 rad/s²

Therefore, the constant angular acceleration of the wheel is approximately 32.35 rad/s².

Learn more about angular acceleration here:

https://brainly.com/question/30237820

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