Answer :
The coefficient of performance (COP) of the refrigerator, which accepts heat at a rate of 10 kW and consumes power at a rate of 5 kW, is 2.00. Therefore the correct answer is 1) 2.00.
The COP of a refrigerator is defined as the amount of heat removed from the cold reservoir Qc divided by the work W done to remove that heat, which is COPref = Qc/W. Given that the refrigerator accepts heat at a rate of 10 kW (this is Qc) and consumes power at a rate of 5 kW (this is W), the COP can be calculated as follows:
COPref = Qc / W = 10 kW / 5 kW = 2.0
The coefficient of performance or COP of a heat pump, refrigerator or air conditioning system is a ratio of useful heating or cooling provided to work required. Higher COPs equate to lower operating costs. The Co-efficient of performance (COP) is an expression of the efficiency of a heat pump. When calculating the COP for a heat pump, the heat output from the condenser (Q) is compared to the power supplied to the compressor (W). COP = |Q|. Therefore the correct answer is 1) 2.00.
