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A rectangular beam has a cross-section of 5 cm wide by 10 cm deep and a maximum shear force of 2250 N. What is the maximum shear stress in the beam?

Answer :

Final answer:

The maximum shear stress in the given rectangular beam, calculated using the shear force and the cross-sectional area, is 450 kPa.

Explanation:

The shear stress in a rectangular beam can be found using the formula for shear stress, which is the force divided by the area. In this case, the shear force is given as 2250 N and the cross-sectional area of the beam can be calculated by multiplying the width and depth of the beam (5 cm x 10 cm = 50 cm² or 0.0050 m² when converted to meters).

So, the shear stress, denoted by 'τ', is calculated as:

τ = F/A

Substituting the given values into the formula, we get:

τ = 2250 N / 0.0050 m² = 450,000 Pa or 450 kPa (kilo-pascals).

This is the maximum shear stress in the beam.

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