Answer :
To determine the pressure exerted by the cabinet on the floor, we use the formula:
[tex]\[ P = \frac{F}{A} \][/tex]
where:
- [tex]\( P \)[/tex] is the pressure,
- [tex]\( F \)[/tex] is the force (or weight in this context),
- [tex]\( A \)[/tex] is the contact area.
Given:
- The weight [tex]\( F \)[/tex] of the cabinet is 100 Newtons (N),
- The contact area [tex]\( A \)[/tex] is [tex]\( 0.5 \, \text{m}^2 \)[/tex].
Now, plug in the values:
[tex]\[ P = \frac{100 \, \text{N}}{0.5 \, \text{m}^2} \][/tex]
[tex]\[ P = 200 \, \text{Pa} \][/tex]
Therefore, the pressure exerted by the cabinet on the floor is [tex]\( 200 \, \text{Pa} \)[/tex].
Among the choices given:
- 0.005 Pa
- 50 Pa
- 200 Pa
- 100.5 Pa
The correct answer is [tex]\( 200 \, \text{Pa} \)[/tex].
[tex]\[ P = \frac{F}{A} \][/tex]
where:
- [tex]\( P \)[/tex] is the pressure,
- [tex]\( F \)[/tex] is the force (or weight in this context),
- [tex]\( A \)[/tex] is the contact area.
Given:
- The weight [tex]\( F \)[/tex] of the cabinet is 100 Newtons (N),
- The contact area [tex]\( A \)[/tex] is [tex]\( 0.5 \, \text{m}^2 \)[/tex].
Now, plug in the values:
[tex]\[ P = \frac{100 \, \text{N}}{0.5 \, \text{m}^2} \][/tex]
[tex]\[ P = 200 \, \text{Pa} \][/tex]
Therefore, the pressure exerted by the cabinet on the floor is [tex]\( 200 \, \text{Pa} \)[/tex].
Among the choices given:
- 0.005 Pa
- 50 Pa
- 200 Pa
- 100.5 Pa
The correct answer is [tex]\( 200 \, \text{Pa} \)[/tex].
