Middle School

A rectangular athletic field is twice as long as it is wide. If the perimeter of the athletic field is 120 yards, what are the dimensions? What is the width?

Answer :

L=2W
P=2(L+W)
P=120
120=2(L+W)
divide by 2
60=L+W
sub 2W for L
60=2W+W
60=3W
divide by 60 both sides
20=W

width=20 yd
Given: [tex]l=2w[/tex] and [tex]P=120yd[/tex] find [tex]l[/tex] and [tex]w[/tex].

[tex]P=2l+2w[/tex]
[tex]120=2l+l[/tex]
[tex]3l=120[/tex]
[tex]l=40[/tex]

[tex]l=2w[/tex]
[tex]w=\frac{l}{2}[/tex]
[tex]w=\frac{40}{2}[/tex]
[tex]w=20[/tex]

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