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A racing car moving at 50.5 m/s engages a parachute and braking system and comes to rest 5.75 s later. Determine the displacement of the racing car during this deceleration period.

Answer :

The racing car with the parachute open and the breaks on with initial velocity of 50.5 m/s will come to a stop after traveling a distance of 145 metres.

What are Newton's law of motion?

Newton gave three laws of motion which can be utilised to find the velocity, acceleration and displacement of a body. These laws are only applicable for constant acceleration.

What is re-tardation in physics?

Re-tardation is a physical quantity that refers to the change of velocity per unit time it decreases the velocity of the object also known as de-acceleration.

Given:

Initial velocity of the racing car = 50.5 m/s

Final velocity of the racing car = 0 m/s

Time of re-tardation= 5.75 seconds

To find:

Displacement of the racing car while regarding

Using Newton's second law of motion.

i.e. s = u × t + 0.5 × a × t × t

Where,

s is the displacement of the racing car before coming to a stop.

u is the initial velocity of the racing car.

a is the acceleration/ re-tardation of the racing car.

t is the time taken.

First we will find the acceleration of the car using Newton's first law of motion we get,

v = u + a × t

0 = 50.5 + a × t

-50.5/5.75 = a

a = - 8.8 seconds

Substituting the value in the newton second law of motion we get,

s = 50.5 × 5.75 + 0.5 × (-8.8) × 33

s = 145 meters

Therefore, the racing car with the parachute open and the breaks on with initial velocity of 50.5 m/s will come to a stop after traveling a distance of 145 meters.

Learn more about Newton's law of motion here:

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