High School

A pulley with a diameter of 1 meter is rotating at 600 revolutions per minute (r.p.m.). It is brought to rest in 80 seconds by a constant force of friction on its shaft. How many revolutions does it make before stopping?

A. 200
B. 400
C. 600
D. 500

Answer :

Final answer:

The pulley moves 400 revolutions. Therefore the correct option is b.

Explanation:

To find the number of revolutions the pulley moves, we need to calculate the angular displacement. The angular displacement can be calculated using the formula:
Angular Displacement = (angular velocity) * (time)
Since the pulley is brought to rest, the final angular velocity is 0. The initial angular velocity can be calculated using the formula:

Initial Angular Velocity = (initial angular velocity) - (angular acceleration * time)
Since the pulley is rotating at a constant speed, the angular acceleration is 0. So, the initial angular velocity is equal to the angular velocity.
Let's calculate the initial angular velocity:
Angular velocity = (2π * r) * (rpm / 60)
where r is the radius of the pulley and rpm is the number of revolutions per minute.
Substituting the values:
Angular velocity = (2π * 0.5) * (600 / 60) = π * 10 rad/s
Now, substituting the values into the formula:
Angular Displacement = (π * 10) * 80 = 800π rad
Since there are 2π radians in one revolution, the number of revolutions the pulley moves can be calculated as:
Number of revolutions = (800π) / (2π) = 400

Therefore, the pulley moves 400 revolutions.