High School

A potential difference of 3.10 nV is set up across a 2.09 cm length of copper wire that has a radius of 2.32 mm. How much charge drifts through a cross section in 3.05 ms? Assume that the resistivity of copper is [tex]1.69 \times 10^{-8} \, \Omega \cdot m[/tex].

Answer :

Answer:

drift change = 4.5241 × 10^-7 C

Explanation:

Given data

potential difference = 3.10 nV

length= 2.09 cm

radius = 2.32 mm

to find out

charge drifts through a cross section in 3.05 ms

solution

we will apply here drift change formula that is

drift change = potential difference × π × radius² × time / resistance × length

put all the value and we get drift change

drift change = 3.10 × 10^-9 × π × (0.00232)² × 3.05× 10^(-3) / 1.69×10^(-8) × 0.0209

drift change = 4.5241 × 10^-7 C

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