High School

A point source of electromagnetic radiation has an average power output of 1500 W. What is the maximum value of the electric field at a distance of 3 m from this source in V/m?

A. 500
B. 100
C. 500/3
D. 250/3

Answer :

Final answer:

The maximum electric field at a distance of 3m from a point source of electromagnetic radiation with a 1500W power output is approximately 500 V/m. The correct answer is A. 500.

Explanation:

The maximum electric field at a distance of 3m from a point source of electromagnetic radiation with 1500W average power output can be calculated using the formula:

Electric field (E) = √((2 * power output) / (speed of light * area))

Plugging in the values, we get:

Electric field (E) = √((2 * 1500) / (3 x 10^8 x 4pi x (3)²))

Electric field (E) = √(1000 / (3 x 10⁸ x 36pi))

Electric field (E) ≈ 500 V/m

The correct answer is A. 500.

The electric field (E) is a fundamental concept in physics that describes the influence exerted by electric charges on other charges within the surrounding space.

It is a vector field, meaning it has both magnitude and direction at every point in space.