High School

A plane that is 800 m in the air is trying to land on a runway. The angle of depression to the first runway is 8°. This runway is too busy, so it must land on a second runway with an angle of depression of 7° from the plane. How much further must the plane fly to reach the second runway?

Answer :

The plane must fly approximately 823.19 meters further to reach the second runway.

How to find the distance

To determine how much further the plane must fly to reach the second runway, we can use trigonometry and the concept of angles of depression.

Using the tangent function:

tan(8°) = opposite / adjacent

tan(8°) = 800 / x

x = 800 / tan(8°)

x ≈ 5692.29

Therefore, the horizontal distance from the plane to the first runway is approximately 5692.29 meters.

Also

tan(7°) = 800 / y

y = 800 / tan(7°)

y ≈ 6515.48

the additional horizontal distance

= 6515.58 - 5692.29

= 823.19 m

Learn more about angle of depression at

https://brainly.com/question/17193804

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