Answer :
The velocity of the baseball after 2.5 seconds will be 11.3 m/s.
State first equation of motion?
The first equation of motion is -
v = u + at
Given is a a pitcher threw a baseball straight up at 35.8 m/s
initial velocity [v] = 35.8 m/s
acceleration [g] = - 9.8 m/s²
time [t] = 2.5 seconds
Using first equation of motion, we get -
v = u + at
v = 35.8 - 9.8 x 2.5
v = 35.8 - 24.5
v = 11.3 m/s
Therefore, the velocity of the baseball after 2.5 seconds will be 11.3 m/s.
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ok the velocity of an object in free fall is given by the equation :
v=v0-gt, where v0 is the original velocity, g is the gravitational constant (9.8 m/s^2) and t is the time.
so, we substitute values into this equation. v=35.8-9.8*2.5; v=11.3 m/s
v=v0-gt, where v0 is the original velocity, g is the gravitational constant (9.8 m/s^2) and t is the time.
so, we substitute values into this equation. v=35.8-9.8*2.5; v=11.3 m/s
