High School

A piece of an unknown solid substance weighs 0.432 kg and requires 8460 J to increase its temperature from 193 K to 689 K. What is the specific heat of the substance?

Answer :

Final answer:

The specific heat of the unknown substance is calculated using the formula Q = mcΔT and the given values; the result is approximately 39.61 J/kg.K.

Explanation:

The subject of this question is to calculate the specific heat of an unknown substance. Specific heat can be calculated using the formula Q = mcΔT, where Q is the heat energy transferred, m is the mass of the substance, c is the specific heat, and ΔT is the change in temperature. Rearranging for c gives us c = Q/(mΔT).

Given in the problem, Q = 8460 J (joules), m = 0.432 kg (kilograms), and ΔT = 689K - 193K = 496 K (kelvin).

Substituting these values into the equation gives us c = 8460 J /(0.432 kg * 496 K) = 39.61 J/kg.K. This is the specific heat of the unknown substance.

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