Answer :
Final answer:
To warm a 35.5 g piece of aluminum from 34.9°C to 82.7°C, 367.035 calories are needed using the specific heat capacity of 0.215 calories/g°C.
Explanation:
To calculate the calories needed to warm a piece of aluminum from 34.9°C to 82.7°C, we need to use the formula:
Q = mcΔT
where:
- Q is the heat energy (in calories)
- m is the mass of the aluminum (in grams)
- c is the specific heat capacity of aluminum (in calories/g°C)
- ΔT is the change in temperature (°C)
For aluminum, the specific heat capacity (c) is approximately 0.215 calories/g°C. The mass (m) is given as 35.5 g, and the change in temperature (ΔT) is:
82.7°C - 34.9°C = 47.8°C
Now, we can calculate the energy needed:
Q = m × c × ΔT
Q = (35.5 g) × (0.215 cal/g°C) × (47.8°C)
Q = 367.035 calories
Therefore, 367.035 calories are needed to warm the piece of aluminum to 82.7°C.
Learn more about Calculating Heat Energy here:
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