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------------------------------------------------ How many grams of Kr are in a 3.95 L cylinder at 97.3 ∘C and 2.80 atm?

To find the number of grams of Kr in a cylinder, use the ideal gas law equation PV = nRT. Convert the temperature from Celsius to Kelvin, plug the values into the equation, solve for n, and then convert moles to grams using the molar mass of Kr.

Explanation:

To calculate the number of grams of Kr in a cylinder, we need to use the ideal gas law equation: PV = nRT. In this case, P = 2.80 atm, V = 3.95 L, T = 97.3 °C (convert to Kelvin by adding 273.15), and R is the ideal gas constant. We need to solve for n (the number of moles of Kr) and then convert it to grams using the molar mass of Kr.

1. Convert temperature from Celsius to Kelvin: 97.3 °C + 273.15 = 370.45 K

2. Plug the values into the ideal gas law equation: (2.80 atm)(3.95 L) = n(0.0821 L·atm/(mol·K))(370.45 K)

3. Solve for n: n = (2.80 atm)(3.95 L) / (0.0821 L·atm/(mol·K))(370.45 K)

4. Convert moles of Kr to grams using the molar mass of Kr: n (mol) × molar mass Kr (g/mol) = grams of Kr

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