A man seeking to set a world record wants to tow a 118,000-kg airplane along a runway by pulling horizontally on a cable attached to the airplane. The mass of the man is 93 kg, and the coefficient of static friction between his shoes and the runway is 0.79. What is the greatest acceleration the man can give the airplane? Assume that the airplane is on wheels that turn without any frictional resistance.

The force produced when two surfaces slide past one another and make contact is known as frictional force. The surface texture of these forces and the amount of force pressing them together have the biggest impact.

Mass of the person

m1 = 93kg

Mass of the air plane

m2 = 118000 kg

Coefficient of static friction between the shoes of the person and floor

μs=0.79

Acceleration due to gravity

g=9.8m/s^2

The maximum force the person can apply on the floor is equal to his weight

F = w = m1∗g

= 93∗9.8=911.4 N

The maximum frictional force he can get from the floor is the product of coefficient of static friction and normal reaction

Ff = μs∗N

= μs∗W

= 0.79 ∗ 911.4 = 720 N

Let's assume that the individual is able to use or apply the entire frictional force in pushing the airplane.

Following that, the relationship can be used to determine the acceleration an air plane created.

Ff = m2 * a

a = Ff/m2

= 720/118000

= 6.102*10^-3 m/s^2

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