Answer :
The buoyant force on the submerged ebony wood log is approximately 1617 Newtons.
The buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. In this case, since the ebony wood log is totally submerged, the volume of water it displaces is equal to the volume of the log itself.
To find the buoyant force, we use the equation
Ww = mwg, where mw is the mass of the water displaced and g is the acceleration due to gravity (9.80 m/s²).
The mass of the water displaced can be found by assuming the log displaces a volume of water equal to its own mass divided by the density of water, which is 1000 kg/m³ (the approximate density of freshwater).
So, if the mass of the log is 165 kg, it displaces 165 kg of water.
Therefore, the buoyant force is equal to
165 kg × 9.80 m/s², which is approximately 1617 N (Newton).
Answer:
F = 1618.65[N]
Explanation:
To solve this problem we use the following equation that relates the mass, density and volume of the body to the floating force.
We know that the density of wood is equal to 750 [kg/m^3]
density = m / V
where:
m = mass = 165[kg]
V = volume [m^3]
V = m / density
V = 165 / 750
V = 0.22 [m^3]
The floating force is equal to:
F = density * g * V
F = 750*9.81*0.22
F = 1618.65[N]
