College

A footballer kicks a ball at an angle of 45° with the horizontal. If the ball was in the air for 10 seconds and lands 4000 meters away, determine its initial speed.

A. 200 m/s
B. 20 m/s
C. 4000 m
D. 40 m/s

Answer :

Final answer:

To determine the initial speed of the ball, we use the horizontal range formula and plug in the given values to find that the initial speed is approximately 566.946 m/s.


Explanation:

To determine the initial speed of the ball, we can use the horizontal range formula:

R = V0 * cos(theta) * t

where R is the range (4000 m), V0 is the initial speed, theta is the angle of projection (45 degrees), and t is the time of flight (10 s).

Plugging in the given values:

4000 = V0 * cos(45) * 10

Simplifying the equation:

V0 = 4000 / (10 * cos(45)) = 4000 / (10 * 0.7071) = 4000 / 7.071 = 566.946

Therefore, the initial speed of the ball is approximately 566.946 m/s.


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