We need to find the weight of a person at a certain period of time.
The weight of the person at the required time is A. [tex]182\dfrac{1}{3}\ \text{lb}[/tex]
Initial weight of person = [tex]170\dfrac{2}{3}[/tex] pounds.
Weight gained = [tex]25\dfrac{5}{12}[/tex] pounds
Weight lost = [tex]10\dfrac{1}{4}+3\dfrac{1}{2}[/tex] pounds
So, weight of the person is
[tex]170\dfrac{2}{3}+25\dfrac{5}{12}-(10\dfrac{1}{4}+3\dfrac{1}{2})\\ =170+\dfrac{2}{3}+25+\dfrac{5}{12}-(10+\dfrac{1}{4}+3+\dfrac{1}{2})\\ =195+\dfrac{8+5}{12}-13-\dfrac{1+2}{4}\\ =182+\dfrac{13}{12}-\dfrac{3}{4}\\ =182+\dfrac{13-3}{12}\\ =182+\dfrac{10}{12}\\ =182+\dfrac{1}{3}=182\dfrac{1}{3}[/tex]
The weight of the person at the required time is A. [tex]182\dfrac{1}{3}\ \text{lb}[/tex]
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Answer:
182 1/3 lbs
MAY: weight = 170 2/3
Summer: gained 25 5/12
New weight : 170 2/3 + 25 5/12
Get a common denominator of 12
170 2/3 *4/4 + 25 5/12
170 8/12 + 25 5/12 = 195 13/12
The he lost 10 1/4 during the first week of fall practice
195 13/12 - 10 1/4
We need to get a common denominator of 12
195 13/12 - 10 1/4*3/3
195 13/12 - 10 3/12
185 10/12
The he lost another 3 1/2 pound during the second week
185 10/12 - 3 1/2
We need to get a common denominator of 12
185 10/12 - 3 1/2 * 6/6
185 10/12 - 3 6/12
182 4/12
Simplify the fraction
182 1/3 lbs
Hope this helps!
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