Answer :
It takes approximately 7.52 seconds for the Time to stop a car.
The situation described in the question can be resolved using the equations of motion, specifically the formula: [tex]v^2 = u^2 + 2as[/tex] where 'v' is the final velocity, 'u' is the initial velocity, 'a' is the acceleration, and 's' is the distance covered.
Given in the question, u = 10.9 m/s, v = 0 (because the car comes to a stop), and s = -4.1 m (the distance is considered negative because the direction of motion is reversed during braking).
Plugging these values into the equation, we get a =[tex]- (v^2 - u^2) / 2s = - ((0)^2 - (10.9)^2) / 2* -4.1 = 1.45 m/s^2[/tex]
Here the acceleration a is positive because the car is decelerating.
To find the time it takes for the car to stop, use another equation of motion: v = u + at => 0 = 10.9 + 1.45*t.
Solving for 't' gives us the time it takes for the car to stop which is around 7.52 seconds.
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