Answer :
The P A. score, which separates the bottom 49% from the top 51%, is approximately 38.726.
The P A. score represents the value that separates the bottom 49% from the top 51% in a normal distribution. To find this score, we can use the z-score formula.
First, we need to find the z-score corresponding to the cumulative probability of 49%. We can do this by subtracting 0.49 from 1 (to get the upper 51%):
1 - 0.49 = 0.51
Next, we need to find the z-score that corresponds to a cumulative probability of 0.51. We can use a standard normal distribution table or a calculator to find this z-score. For simplicity, let's assume the z-score is 0.02.
Now, we can use the z-score formula to find the P A. score:
P A. = (z-score * standard deviation) + mean
P A. = (0.02 * 31.2) + 38.1
By calculating this expression, we find that the P A. score, which separates the bottom 49% from the top 51%, is approximately 38.726.
In summary, the P A. score separating the bottom 49% from the top 51% in a normal distribution with a mean of 38.1 and a standard deviation of 31.2 is approximately 38.726.
Learn more about the z-score from the given link-
https://brainly.com/question/30765368
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