Answer :
The surface speed of a cylindrical part with a 50 mm diameter rotating at 600 rpm is calculated by finding the circumference and multiplying by rpm, resulting in approximately 94 m/min. Therefore, the correct option is A.
The surface speed of a cylindrical part rotating at 600 revolutions per minute (rpm) with a diameter of 50 mm can be calculated using the formula for the circumference of a circle multiplied by the number of revolutions per minute. The formula for circumference is C = (pi) * d, where d is the diameter.
The diameter given is 50 mm, so C = (pi) * 50 mm. Therefore, the circumference C is approximately 157 mm (since (pi) is approximately 3.14).
Surface speed = circumference * RPM = 157 mm * 600 min⁻¹. Converting this to meters, we have 0.157 m * 600 min⁻¹ = 94.2 m/min. Thus, the correct answer to the student's question is (A) about 94 m/min.
