Answer :
The inductance of the solenoid which generates the emf of 0.075 V is 508 H
The change of current in the solenoid = 38.1 A/s
The emf generated by the solenoid = 75 x 10⁻³ V
The inductance of the solenoid can be found using the formula,
e = L dI/dt
where e is the emf generated by the solenoid
L is the inductance of the solenoid
dI/dt is the change of current in the solenoid
Let us substitute the known value in the above equation, we get
0.075 = L x 38.1
L = 38.1 / 0.075
= 508 H
Thus, the inductance of the solenoid is 508 H
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