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------------------------------------------------ A current that changes at a rate of 38.1 A/s generates an EMF of 75 mV in a solenoid. What is the inductance of the solenoid?

Answer :

The inductance of the solenoid which generates the emf of 0.075 V is 508 H

The change of current in the solenoid = 38.1 A/s

The emf generated by the solenoid = 75 x 10⁻³ V

The inductance of the solenoid can be found using the formula,

e = L dI/dt

where e is the emf generated by the solenoid

L is the inductance of the solenoid

dI/dt is the change of current in the solenoid

Let us substitute the known value in the above equation, we get

0.075 = L x 38.1

L = 38.1 / 0.075

= 508 H

Thus, the inductance of the solenoid is 508 H

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