Answer :
The saturation is 33%, the total unit weight is 107.5 lbs/ft^3, the void ratio is 0.43 and the porosity is 30%.
To calculate the saturation, we need to find the weight of water in the soil, which is 25% of the total weight of 215 lbs. So, the weight of water is 25/100 * 215 lbs = 53.75 lbs.
Next, we find the weight of solids in the soil, which is 215 lbs - 53.75 lbs = 161.25 lbs.
The saturation (S) is the ratio of the weight of water to the weight of solids in the soil and is calculated as follows:
S = 53.75 lbs / 161.25 lbs = 0.33 or 33%.
The total unit weight of the soil can be calculated using the following formula:
γ = (W_water + W_solids) / V
where W_water is the weight of water, W_solids is the weight of solids, and V is the volume of the soil.
Substituting the values, we get
γ = (53.75 lbs + 161.25 lbs) / (2 ft^3) =
= 215 lbs / (2 ft^3) = 107.5 lbs/ft^3
The void ratio (e) is the ratio of the volume of voids in the soil to the volume of solids in the soil, and can be calculated as follows:
e = V_voids / V_solids = (V - V_solids) / V_solids = (V - W_solids / γ_solids) / (W_solids / γ_solids)
Substituting the values, we get
e = (2 ft^3 - 161.25 lbs / 2.7) / (161.25 lbs / 2.7) = 0.43
Finally, the porosity (n) is the ratio of the volume of voids in the soil to the total volume of soil and is given by:
n = V_voids / V = e / (1 + e) = 0.43 / (1 + 0.43) = 0.43 / 1.43 = 0.30 or 30%.
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