Answer :
The empirical formula of the compound is found to be C₃H₄NO₂.
To determine the empirical formula, we need to find the simplest whole number ratio of the elements in the compound. We can start by converting the given masses of each element into moles using their respective molar masses.
Carbon (C): 97.6 g C / 12.01 g/mol = 8.13 mol C
Hydrogen (H): 4.9 g H / 1.01 g/mol = 4.85 mol H
Oxygen (O): 52 g O / 16.00 g/mol = 3.25 mol O
Nitrogen (N): 45.5 g N / 14.01 g/mol = 3.25 mol N
Dividing by the the number of moles of each element,
Carbon: 8.13 mol C / 3.25 mol = 2.50 (approximately)
Hydrogen: 4.85 mol H / 3.25 mol = 1.50 (approximately)
Oxygen: 3.25 mol O / 3.25 mol = 1.00
Nitrogen: 3.25 mol N / 3.25 mol = 1.00
Rounding these ratios to the nearest whole number, we get the empirical formula C₃H₄NO₂, which represents the simplest ratio of atoms in the compound.
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