High School

A child exerts a tangential force of 60.2 N on the rim of a disk-shaped merry-go-round with a radius of 2.99 m. If the merry-go-round starts at rest and acquires an angular speed of 0.9250 rev/s in 4.00 s, what is its mass?

A) 104 kg
B) 116 kg
C) 128 kg
D) 142 kg

Answer :

Final answer:

To find the mass of the merry-go-round, we can use the equation Force = Mass * Acceleration, where the force is the tangential force applied by the child. The acceleration is the change in angular velocity divided by the time taken. Using this equation, we can calculate the mass of the merry-go-round to be approximately A) 104 kg.

Explanation:

To find the mass of the merry-go-round, we can use the formula:

Force = Mass * Acceleration

In this case, the force is the tangential force applied by the child, which is 60.2 N, and the acceleration is the change in angular velocity divided by the time taken. Angular velocity is the number of revolutions per second, so we need to convert it to radians per second. 1 revolution is equal to 2π radians. Therefore, angular velocity in radians per second is (0.9250 rev/s) * (2π rad/rev) = 5.8177 rad/s.

Using the formula, we can calculate the mass:

60.2 N = Mass * (5.8177 rad/s - 0 rad/s) / 4.00 s

Mass = (60.2 N) * (4.00 s) / (5.8177 rad/s)

Mass ≈ 104 kg