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1. Wine is approximately 12% ethanol [tex]C_2H_5OH[/tex] by volume. Ethanol has a molar mass of 46.06 g/mol and a density of 0.789 g/mL. How many moles of ethanol are present in a 750 mL bottle of wine?

Answer :

Hey there!:

Total volume of wine = 750ml

volume ℅ of ethanol = 12
%

volume of ethanol = (12ml/100ml)*750ml = 90ml


Density of Ethanol = 0.789 g/ml


Mass of Ethanol = 0.789 g/ml × 90ml = 71.01 g


Molar mass of ethanol = 46 g/mol Nº of mole of ethanol = Mass/molar mass

=> 71.01 g /46(g/mol)= 1.5437 moles

Hope this helps!

1.541 moles of ethanol are present in a 750 mL bottle of wine.

How to find the number of moles ?

Number of moles = [tex]\frac{\text{Mass}}{\text{Molar mass}}[/tex]

What is Density ?

The substance per unit volume is called Density. SI unit of density is kg/m.

It is expressed as:

Density = [tex]\frac{\text{Mass}}{\text{Volume}}[/tex]

Volume of ethanol = 12%

= [tex]\frac{12}{100}[/tex]

= 0.12

Volume of ethanol = 0.12 × 750

= 90

Density of ethanol = [tex]\frac{\text{Mass of ethanol}}{\text{Volume of ethanol}}[/tex]

0.789 g/mL = [tex]\frac{\text{Mass of ethanol}}{90}[/tex]

Mass of ethanol = 0.789 × 90

= 71.01 g

Now put the value in above formula we get

Number of moles = [tex]\frac{\text{Mass}}{\text{Molar mass}}[/tex]

= [tex]\frac{71.01\ g}{46.06\ \text{g/mol}}[/tex]

= 1.541 mol

Thus from the above conclusion we can say that 1.541 moles of ethanol are present in a 750 mL bottle of wine.

Learn more about the Number of mole here: https://brainly.com/question/1575466

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