Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ A certain type of bacteria, given a favorable growth medium, doubles in population every 4 hours. Given that there were approximately 100 bacteria to start with, how many bacteria will there be in a day and a half?

To calculate the bacterial population after a day and a half with an initial count of 100 and a doubling time of 4 hours, we find 9 doubling periods in 36 hours. Using the exponential growth formula N = N0 * 2^n, we calculate the final population to be 51,200 bacteria.

Explanation:

The question involves an understanding of exponential growth, specifically concerning a population of bacteria. Given that the bacteria double in population every 4 hours, we first need to determine the number of doubling periods in a day and a half, which is equal to 36 hours. Since there are 4 hours in each doubling period, we divide 36 by 4 to get 9 doubling periods.

To find out the total number of bacteria after 36 hours, we use the formula for exponential growth:

N = N0 * 2^n

where N is the final population size, N0 is the initial population size, and n is the number of doubling periods.

Substituting the given values:

N = 100 * 2^9

N = 100 * 512

N = 51,200

Therefore, after a day and a half, there will approximately be 51,200 bacteria.

Learn more about Exponential Bacterial Growth here:

https://brainly.com/question/30970589

#SPJ2