High School

A car of mass 1000 kg is moving at a speed of 90 km/h. Brakes are applied, and the car stops at a distance of 15 m from the braking point. If the car stops in 25 seconds after braking, calculate the average power of the brakes.

Answer :

Answer:

Pavg =24.4×20800

Explanation:

1st u(initial velocity)=90×5/18=25m/s

v^2-u^2=2as........v=0

a=-20.8 then force=ma =1000×(-20.8)=-20800

P initial=f×u and P final=f×s/t

Pavg=Pi-Pf=fu-fs/t=f(25-15/25)=f(25-0.6)

Pavg=20800×24.4

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