Answer :
Sure, let's break down and solve the equation step-by-step.
Given equation:
[tex]\[ 4x - x + 172 = 2640 \][/tex]
First, we simplify the left side by combining like terms. Here, [tex]\(4x - x\)[/tex] simplifies to [tex]\(3x\)[/tex]:
[tex]\[ 3x + 172 = 2640 \][/tex]
Next, we need to solve for [tex]\(x\)[/tex]. To do this, we first isolate [tex]\(3x\)[/tex] by subtracting 172 from both sides of the equation:
[tex]\[ 3x + 172 - 172 = 2640 - 172 \][/tex]
This simplifies to:
[tex]\[ 3x = 2468 \][/tex]
To find [tex]\(x\)[/tex], we then divide both sides by 3:
[tex]\[ x = \frac{2468}{3} \][/tex]
When we solve this division:
[tex]\[ x \approx 822.67 \][/tex]
So, the solution is:
[tex]\[ x \approx 822.67 \][/tex]
This tells us that [tex]\(x\)[/tex], which represents some quantity in Denise's purchase, is approximately [tex]\(822.67\)[/tex]. To understand the full context, you would typically need additional information about what [tex]\(x\)[/tex] represents in terms of the purchase. However, this is the value of [tex]\(x\)[/tex] that makes the equation true.
Given equation:
[tex]\[ 4x - x + 172 = 2640 \][/tex]
First, we simplify the left side by combining like terms. Here, [tex]\(4x - x\)[/tex] simplifies to [tex]\(3x\)[/tex]:
[tex]\[ 3x + 172 = 2640 \][/tex]
Next, we need to solve for [tex]\(x\)[/tex]. To do this, we first isolate [tex]\(3x\)[/tex] by subtracting 172 from both sides of the equation:
[tex]\[ 3x + 172 - 172 = 2640 - 172 \][/tex]
This simplifies to:
[tex]\[ 3x = 2468 \][/tex]
To find [tex]\(x\)[/tex], we then divide both sides by 3:
[tex]\[ x = \frac{2468}{3} \][/tex]
When we solve this division:
[tex]\[ x \approx 822.67 \][/tex]
So, the solution is:
[tex]\[ x \approx 822.67 \][/tex]
This tells us that [tex]\(x\)[/tex], which represents some quantity in Denise's purchase, is approximately [tex]\(822.67\)[/tex]. To understand the full context, you would typically need additional information about what [tex]\(x\)[/tex] represents in terms of the purchase. However, this is the value of [tex]\(x\)[/tex] that makes the equation true.