Answer :
A car battery does 170 J of work on the charge passing through it as it starts an engine. When the emf (electromotive force) is reduced to 6 V, the amount of charge passing through the battery increases to approximately 28.33 coulombs.
(a) To find the amount of charge passing through the car battery during the start, we can use the equation W = Q x V, where W is the work done, Q is the charge, and V is the emf. Rearranging the equation, we get Q = W/V. Substituting the given values, Q = 170 J / 12 V = 14.17 C. Therefore, 14.17 Coulombs of charge pass through the car battery during the start.
Or To find the amount of charge that passes through the car battery during the start, we can use the formula for work: Work = Voltage (V) × Charge (Q). In this case, the work done is 170 J and the emf of the battery is 12 V.
170 J = 12 V × Q
To find the charge (Q), we can rearrange the formula and divide both sides by 12 V:
Q = 170 J / 12 V
Q ≈ 14.17 coulombs
So, approximately 14.17 coulombs of charge pass through the battery during the start.
(b) If the emf is reduced to 6 V, the amount of charge passing through the battery will decrease. Using the same equation Q = W/V, we can calculate the new amount of charge passing through the battery. Q = 170 J / 6 V = 28.33 C. Therefore, 28.33 Coulombs of charge will pass through the car battery if the emf is reduced to 6 V.
Or If the emf is reduced to 6 V, we can use the same formula to determine how the amount of charge passing through the battery changes:
170 J = 6 V × Q
To find the new charge (Q), we can rearrange the formula and divide both sides by 6 V:
Q = 170 J / 6 V
Q ≈ 28.33 coulombs
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