Answer :
To solve this problem, we first note the values given:
- The force applied by the brakes is [tex]$F = 20000 \, \text{N}$[/tex].
- The car stops over a distance of [tex]$d = 25 \, \text{m}$[/tex].
The work [tex]$W$[/tex] done by a force is determined by the formula:
[tex]$$
W = F \cdot d
$$[/tex]
However, since the braking force acts in the opposite direction to the car's motion, the work done is negative. Therefore, we calculate:
[tex]$$
W = - (20000 \, \text{N}) \times (25 \, \text{m}) = -500000 \, \text{J}
$$[/tex]
Thus, the brakes do [tex]$-500000 \, \text{J}$[/tex] of work on the car.
- The force applied by the brakes is [tex]$F = 20000 \, \text{N}$[/tex].
- The car stops over a distance of [tex]$d = 25 \, \text{m}$[/tex].
The work [tex]$W$[/tex] done by a force is determined by the formula:
[tex]$$
W = F \cdot d
$$[/tex]
However, since the braking force acts in the opposite direction to the car's motion, the work done is negative. Therefore, we calculate:
[tex]$$
W = - (20000 \, \text{N}) \times (25 \, \text{m}) = -500000 \, \text{J}
$$[/tex]
Thus, the brakes do [tex]$-500000 \, \text{J}$[/tex] of work on the car.
