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(a) Calculate the magnitude of the gravitational force exerted by Mars on a 67 kg human standing on the surface of Mars.

Given:
- Mass of Mars: [tex]6.4 \times 10^{23} \text{ kg}[/tex]
- Radius of Mars: [tex]3.4 \times 10^6 \text{ m}[/tex]
- Mass of the human: [tex]67 \text{ kg}[/tex]

Answer :

Answer:

2474.13 N

Explanation:

From Newton's Law of universal gravitation,

F = Gmm'/r².................... Equation 1

Where F = gravitational force, m = mass of the human, m' = mass of mars, G = Gravitational acceleration, r = radius of mars.

Given : m = 67 kg, m' = 6.4×10²³ kg, r = 3.4×10⁶ m

Constant: G = 6.67×10⁻¹¹ Nm²/kg².

Substituting into equation 1

F = 67(6.4×10²³)(6.67×10⁻¹¹)/ (3.4×10⁶)²

F = 28600.96×10¹²/11.56×10¹²

F = 2474.13 N.

Hence the gravitational force = 2474.13 N

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