High School

A burglar attempts to drag a 116 kg metal safe across a polished wood floor. Assume that the coefficient of static friction is 0.4, the coefficient of kinetic friction is 0.3, and that the burglar can apply a pushing force of 533 N on the metal safe. What is the acceleration of the metal safe across the floor?

Answer :

The acceleration of the metal safe across floor is 1.65 m/s²

What is force?

A force can change the velocity of an object with mass, i.e. accelerate it. Forces can also be described intuitively by pushing or pulling. A force has both magnitude and direction and is a vector quantity.

For the given case,

The weight of the metal safe is calculated as:

W = mg

W = 116 x 9.8

W = 1136.8 N

The frictional force on metal safe is:

Fₓ = μFₙ

Fₓ = 0.3 × 1136.8

Fₓ = 341.04 N

The net horizontal force applied on the metal safe is:

Fₙ = Applied horizontal force - frictional force

Fₙ = 533 - 341.04

Fₙ = 191.96 N

The acceleration of the safe across floor is:

F = ma

a = Fₙ /m

a = 191.96/116

a = 1.65 m/s²

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