College

One week, a construction worker bought [tex]$40 \frac{1}{10}$[/tex] pounds of nails. The next week, he bought [tex]$2 \frac{1}{2}$[/tex] times as many nails as the week before. How many pounds of nails did he buy the second week?



A. [tex]$16 \frac{1}{25}$[/tex] lb

B. [tex]$99 \frac{1}{4}$[/tex] lb

C. [tex]$80 \frac{1}{20}$[/tex] lb

D. [tex]$100 \frac{1}{4}$[/tex] lb

Answer :

First, convert the mixed numbers into improper fractions.

1. The first week's nails weigh
$$40\frac{1}{10} = 40 + \frac{1}{10} = \frac{40 \times 10 + 1}{10} = \frac{401}{10}.$$

2. The multiplier for the second week is
$$2\frac{1}{2} = 2 + \frac{1}{2} = \frac{2 \times 2 + 1}{2} = \frac{5}{2}.$$

Next, multiply the weight from the first week by the multiplier:

$$
\frac{401}{10} \times \frac{5}{2} = \frac{401 \times 5}{10 \times 2} = \frac{2005}{20}.
$$

Now, simplify the fraction:

$$
\frac{2005}{20} = \frac{2005 \div 5}{20 \div 5} = \frac{401}{4}.
$$

To express $\frac{401}{4}$ as a mixed number, divide 401 by 4:

- The quotient is 100, because $100 \times 4 = 400$.
- The remainder is $401 - 400 = 1$.

Thus,
$$
\frac{401}{4} = 100\frac{1}{4}.
$$

So, the construction worker bought
$$\boxed{100\frac{1}{4}\ \text{lb}}$$
of nails in the second week.