Answer :
Hello!
A bicyclist of mass 112 kg rides in a circle at a speed of 8.9 m/s. If the radius of the circle is 15.5 m, what is the centripetal force on the bicyclist ?
We have the following data:
Centripetal Force = ? (Newton)
m (mass) = 112 Kg
s (speed) = 8.9 m/s
R (radius) = 15.5 m
Formula:
[tex]\boxed{F_{centripetal\:force} = \dfrac{m*s^2}{R}}[/tex]
Solving:
[tex]F_{centripetal\:force} = \dfrac{m*s^2}{R}[/tex]
[tex]F_{centripetal\:force} = \dfrac{112*8.9^2}{15.5}[/tex]
[tex]F_{centripetal\:force} = \dfrac{112*79.21}{15.5}[/tex]
[tex]F_{centripetal\:force} = \dfrac{8871.52}{15.5}[/tex]
[tex]F_{centripetal\:force} = 572.356129...[/tex]
[tex]\boxed{\boxed{F_{centripetal\:force} \approx 572.36\:N}}\end{array}}\qquad\checkmark[/tex]
Answer:
The centripetal force on the bicyclist is approximately 572.36 N
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I Hope this helps, greetings ... Dexteright02! =)
The centripetal force, Fc, is calculated through the equation,
Fc = mv²/r
where m is the mass,v is the velocity, and r is the radius.
Substituting the known values,
Fc = (112 kg)(8.9 m/s)² / (15.5 m)
= 572.36 N
Therefore, the centripetal force of the bicyclist is approximately 572.36 N.
Fc = mv²/r
where m is the mass,v is the velocity, and r is the radius.
Substituting the known values,
Fc = (112 kg)(8.9 m/s)² / (15.5 m)
= 572.36 N
Therefore, the centripetal force of the bicyclist is approximately 572.36 N.
